Circular list iterator in Python
Use itertools.cycle, that’s its exact purpose: Output: (Loops forever, obviously) In order to manually advance the iterator and pull values from it one by one, simply call next(pool):
Use itertools.cycle, that’s its exact purpose: Output: (Loops forever, obviously) In order to manually advance the iterator and pull values from it one by one, simply call next(pool):
To get elements which are in temp1 but not in temp2 : Beware that it is asymmetric : where you might expect/want it to equal set([1, 3]). If you do want set([1, 3]) as your answer, you can use set([1, 2]).symmetric_difference(set([2, 3])).
Try this: The first lambda lets you pick the key, the second one picks the value. You can play with it and make values differ from the keys, like this: If your list contains duplicates, add Distinct() like this: EDIT To comment on the valid reason, I think the only reason that could be valid … Read more
Note: you just need to understand that list comprehension or iterating over a generator expression is explicit looping.
As it currently stands, you are trying to concatenate a string with a list in your final print statement, which will throw TypeError. Instead, alter your last print statement to one of the following:
This traverse generator function can be used to iterate over all the values:
Storing a list of object instances is very simple
Your status-codes are also a collection, so use Contains: or in query syntax:
You need to use an accumulator. While you could do something like this: which will recurse all the way down to the end of the list and then, as each invocation returns, add one to the length, until it gets back to the top level with the correct result. The problem with this approach is that … Read more
I want to make a number , for example 43365644 into single numbers [4,3,3….,4,4] and append it on a list