You need to make your regular expression lazy/non-greedy, because by default, “(.*)” will match all of “file path/level1/level2″ xxx some=”xxx”. Instead you can make your dot-star non-greedy, which will make it match as few characters as possible: Adding a ? on a quantifier (?, * or +) makes it non-greedy. Note: this is only available … Read more
You can’t parse [X]HTML with regex. Because HTML can’t be parsed by regex. Regex is not a tool that can be used to correctly parse HTML. As I have answered in HTML-and-regex questions here so many times before, the use of regex will not allow you to consume HTML. Regular expressions are a tool that … Read more
You can use PATINDEX to find the first index of the pattern (string’s) occurrence. Then use STUFF to stuff another string into the pattern(string) matched. Loop through each row. Replace each illegal characters with what you want. In your case replace non numeric with blank. The inner loop is if you have more than one … Read more
Removing non-alphanumeric chars The following is the/a correct regex to strip non-alphanumeric chars from an input string: Note that \W is the equivalent of [^0-9a-zA-Z_] – it includes the underscore character. To also remove underscores use e.g.: The input is malformed Since the test string contains various escaped chars, which are not alphanumeric, it will … Read more
This should do it for you ^wp.*php$ Matches Doesn’t match
\1 is equivalent to re.search(…).group(1), the first parentheses-delimited expression inside of the regex. It’s also, fun fact, part of the reason that regular expressions are significantly slower in Python and other programming languages than required to be by CS theory.ShareFollowansw
Your negative lookahead solution would e.g. be this: See it here on Regexr
Remove all , and – and other non-digits from the string first. Then use this regex that matches Visa, MasterCard, American Express, Diners Club, Discover, and JCB cards: ^(?:4[0-9]{12}(?:[0-9]{3})?|[25][1-7][0-9]{14}|6(?:011|5[0-9][0-9])[0-9]{12}|3[47][0-9]{13}|3(?:0[0-5]|[68][0-9])[0-9]{11}|(?:2131|1800|35\d{3})\d{11})$
For Java: Quantifiers documentation X, exactly n times: X{n}X, at least n times: X{n,}X, at least n but not more than m times: X{n,m}
You need The [^;] is a character class, it matches everything but a semicolon. To cite the perlre manpage: You can specify a character class, by enclosing a list of characters in [] , which will match any character from the list. If the first character after the “[” is “^”, the class matches any character not in the list. … Read more