str.replace() v2|v3 does not recognize regular expressions. To perform a substitution using a regular expression, use re.sub() v2|v3. For example: In a loop, it would be better to compile the regular expression first:
Regular expressions are used for Pattern Matching. To use in Excel follow these steps: Step 1: Add VBA reference to “Microsoft VBScript Regular Expressions 5.5” Select “Developer” tab (I don’t have this tab what do I do?) Select “Visual Basic” icon from ‘Code’ ribbon section In “Microsoft Visual Basic for Applications” window select “Tools” from the … Read more
Matches the following If you do not want a match on non-US numbers use Update :As noticed by user Simon Weaver below, if you are also interested in matching on unformatted numbers just make the separator character class optional as [\s.-]?
You need to double escape any RegExp characters (once for the slash in the string and once for the regexp): Otherwise, it looks for the end of the line and ‘TESTONE’ (which it never finds). Personally, I’m not a big fan of building regexp’s using strings for this reason. The level of escaping that’s needed … Read more
Flags go at the end. i is for case-Insensitive (or ignore-case)
Let me try to explain this with an example. Consider the following text: Now, if I apply the regex below over it… … I would get the following result: But I don’t care about the protocol — I just want the host and path of the URL. So, I change the regex to include the … Read more
I have this function to validate an email addresses: Is this okay for checking if the email address is valid or not?
The str.split() method without an argument splits on whitespace:
In the first regex, each space character is being replaced, character by character, with the empty string. In the second regex, each contiguous string of space characters is being replaced with the empty string because of the +. However, just like how 0 multiplied by anything else is 0, it seems as if both methods strip spaces in exactly the … Read more
When using “\t”, the escape sequence \t is replaced by Java with the character U+0009. When using “\\t”, the escape sequence \\ in \\t is replaced by Java with \, resulting in \t that is then interpreted by the regular expression parser as the character U+0009. So both notations will be interpreted correctly. It’s just the question when it is replaced with the corresponding character.