Math.round(num * 10) / 10 works, here is an example… if you want it to have one decimal place, even when that would be a 0, then add… EDIT: Add round with precision function… Using this principle, for reference, here is a handy little round function that takes precision… … usage … … defaults to round … Read more
add 0.5 before casting (if x > 0) or subtract 0.5 (if x < 0), because the compiler will always truncate. C++11 also introduces std::round, which likely uses a similar logic of adding 0.5 to |x| under the hood (see the link if interested) but is obviously more robust. A follow up question might be why the float … Read more
Here’s an utility that rounds (instead of truncating) a double to specified number of decimal places. For example: Original version; watch out with this This breaks down badly in corner cases with either a very high number of decimal places (e.g. round(1000.0d, 17)) or large integer part (e.g. round(90080070060.1d, 9)). Thanks to Sloin for pointing this out. I’ve been using the above to round … Read more
I am having trouble rounding a GPA double to 2 decimal places. (ex of a GPA needed to be rounded: 3.67924) I am currently using ceil to round up, but it currently outputs it as a whole number (368) here is what I have right now using the above code with 3.67924 would output 368 … Read more
Math.ceil() is the correct function to call. I’m guessing a is an int, which would make a / 100 perform integer arithmetic. Try Math.ceil(a / 100.0) instead. Outputs:
Here’s an utility that rounds (instead of truncating) a double to specified number of decimal places. For example:
Here’s an utility that rounds (instead of truncating) a double to specified number of decimal places. For example: Original version; watch out with this This breaks down badly in corner cases with either a very high number of decimal places (e.g. round(1000.0d, 17)) or large integer part (e.g. round(90080070060.1d, 9)). Thanks to Sloin for pointing this out. I’ve been using the above to round … Read more
is there a possibility that casting a double created via Math.round() will still result in a truncated down number No, round() will always round your double to the correct value, and then, it will be cast to an long which will truncate any decimal places. But after rounding, there will not be any fractional parts remaining. Here are the docs from Math.round(double): … Read more
You can use the round function, which takes as its first argument the number and the second argument is the precision after the decimal point. In your case, it would be:
I want a to be rounded to 13.95. The round function does not work the way I expected.