It won’t automatically convert (thank god). You’ll have to use the method c_str() to get the C string version. Note that it returns a const char *; you aren’t allowed to change the C-style string returned by c_str(). If you want to process it you’ll have to copy it first: Or in modern C++:
I have two strings like and How to get that this two string are same without breaking the words?
Update: In the latest versions of most popular browsers, you can use replaceAll as shown here: But check Can I use or another compatibility table first to make sure the browsers you’re targeting have added support for it first. For Node and compatibility with older/non-current browsers: Note: Don’t use the following solution in performance critical … Read more
== tests for reference equality (whether they are the same object). .equals() tests for value equality (whether they are logically “equal”). Objects.equals() checks for null before calling .equals() so you don’t have to (available as of JDK7, also available in Guava). Consequently, if you want to test whether two strings have the same value you … Read more
Just use the appropriate method: String#split(). Note that this takes a regular expression, so remember to escape special characters if necessary. there are 12 characters with special meanings: the backslash \, the caret ^, the dollar sign $, the period or dot ., the vertical bar or pipe symbol |, the question mark ?, the … Read more
How about: This is extended slice syntax. It works by doing [begin:end:step] – by leaving begin and end off and specifying a step of -1, it reverses a string.
2230 Links to the documentation: int() str() Conversion to a string is done with the builtin str() function, which basically calls the __str__() method of its parameter.
Here you go: ES5 With ES6 best way would be to use includes function to test if the string contains the looking work.
ECMAScript 6 introduced String.prototype.includes: Expand snippet includes doesn’t have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found:
You opened the file in binary mode: This means that all data read from the file is returned as bytes objects, not str. You cannot then use a string in a containment test: You’d have to use a bytes object to test against tmp instead: or open the file as a textfile instead by replacing … Read more