incompatible types: void cannot be converted to int [duplicate]

Your program does not have to return an int in public static int main. Instead you can have it as void (meaning don’t return anything). You should simply just print your statements and don’t return them. Also the int[] should be String[] and Scanner should check for nextInt() as pointed out in comments!

ERROR: Control may reach end of non-void function /

If you call the function with a first argument of 0 the loop is never executed and the return statement is, thus, never reached. Falling of the end of a non-void function is undefined behavior. My personal guess is that the return statement was meant to one level up, i.e., in the out block: this would guarantee that the function always returns … Read more

variable or field declared void

It for example happens in this case here: Try using std::string instead of just string (and include the <string> header). C++ Standard library classes are within the namespace std::.

What does “javascript:void(0)” mean?

The void operator evaluates the given expression and then returns undefined. The void operator is often used merely to obtain the undefined primitive value, usually using “void(0)” (which is equivalent to “void 0”). In these cases, the global variable undefined can be used instead (assuming it has not been assigned to a non-default value). An explanation is provided here: void operator. The reason you’d want to … Read more

What does “javascript:void(0)” mean?

The void operator evaluates the given expression and then returns undefined. The void operator is often used merely to obtain the undefined primitive value, usually using “void(0)” (which is equivalent to “void 0”). In these cases, the global variable undefined can be used instead (assuming it has not been assigned to a non-default value). An … Read more