What does “control reaches end of non-void function” mean?
The compiler cannot tell from that code if the function will ever reach the end and still return something. To make that clear, replace the last else if(…) with just else.
The compiler cannot tell from that code if the function will ever reach the end and still return something. To make that clear, replace the last else if(…) with just else.
Notice: Undefined variable From the vast wisdom of the PHP Manual: Relying on the default value of an uninitialized variable is problematic in the case of including one file into another which uses the same variable name. It is also a major security risk with register_globals turned on. E_NOTICE level error is issued in case of working with uninitialized variables, however not … Read more
The error is simply used to indicate a division where the denominator is of 0 value, e.g. your data somehow contains incorrect values, for example you try to take the square root of negative numbers, or 1/a where a (which is an array) contains zeroes. I am not able to reproduce the same error from the code … Read more
In this case a[4] is the 5th integer in the array a, ap is a pointer to integer, so you are assigning an integer to a pointer and that’s the warning.So ap now holds 45 and when you try to de-reference it (by doing *ap) you are trying to access a memory at address 45, which is an invalid address, so your program crashes. You should do ap … Read more
Notice: Undefined variable From the vast wisdom of the PHP Manual: Relying on the default value of an uninitialized variable is problematic in the case of including one file into another which uses the same variable name. It is also a major security risk with register_globals turned on. E_NOTICE level error is issued in case of working with uninitialized variables, however not … Read more
Add by Configuration Properties>>C/C++>>Preporocessor>>Preprocessor Definitions>> _CRT_SECURE_NO_WARNINGS
You can’t solve it. Simply answer1.sum()==0, and you can’t perform a division by zero. This happens because answer1 is the exponential of 2 very large, negative numbers, so that the result is rounded to zero. nan is returned in this case because of the division by zero. Now to solve your problem you could: go for a library for … Read more
You can’t solve it. Simply answer1.sum()==0, and you can’t perform a division by zero. This happens because answer1 is the exponential of 2 very large, negative numbers, so that the result is rounded to zero. nan is returned in this case because of the division by zero. Now to solve your problem you could: go … Read more