The problem is that variables declared in one case are still visible in the subsequent cases unless an explicit { } block is used, but they will not be initialized because the initialization code belongs to another case. In the following code, if foo equals 1, everything is ok, but if it equals 2, we’ll accidentally use the i variable which does exist but probably contains garbage. Wrapping … Read more
You just need to return from the main function at some point. The error message says that the function is defined to return a value but you are not returning anything.
I’ve been reading questions here for an hour or two regarding this error I’m getting and most of them forgot to #include string (which I had already done), or to overload the << operator. Here’s the code in question: And the error I’m getting: All I’m trying to do is return the vector. I read … Read more
change to You get the error because compiler thinks of as of function declaration with name ‘foo2’ and the return type ‘Foo’. But in that case If we change to Foo foo2 , the compiler might show the error ” call of overloaded ‘Foo()’ is ambiguous”.
In addition to what visitor said : The function void emplace_back(Type&& _Val) provided by MSCV10 is non conforming and redundant, because as you noted it is strictly equivalent to push_back(Type&& _Val). But the real C++0x form of emplace_back is really useful: void emplace_back(Args&&…); Instead of taking a value_type it takes a variadic list of arguments, so that means that you can now perfectly … Read more
The problem is the two return 0; statements in your function. The function returns a std::string, which has no constructors that accept an int as input. But, it does have a constructor that accepts a const char * pointer, which 0 is implicitly convertible to. However, constructing a std::string with a null char * pointer is undefined behavior, and your implementation has chosen to throw a std::logic_error exception that … Read more
You are mixing c++ and c I/O. In C++ this is,
You are reading an index slowo.size() in slowo, but subscripting it 0-based, so slowo can only be indexed from 0 to slowo.size()-1. You need to change your condition to
stdafx.h is the precompiled header used by Visual Studio, you do not need this. You seem to have missed out the int main() function It is std::endl not std::end1 So something like this:
If you use instead of your compiler will think you want to use a function pointer instead of the method itself, and if you would have wanted to use a function pointer, you would still have to get the address of it (using &). So make sure you don’t forget your () after a function … Read more