C++ int float casting
Integer division occurs, then the result, which is an integer, is assigned as a float. If the result is less than 1 then it ends up as 0. You’ll want to cast the expressions to floats first before dividing, e.g.
Integer division occurs, then the result, which is an integer, is assigned as a float. If the result is less than 1 then it ends up as 0. You’ll want to cast the expressions to floats first before dividing, e.g.
The problem is the two return 0; statements in your function. The function returns a std::string, which has no constructors that accept an int as input. But, it does have a constructor that accepts a const char * pointer, which 0 is implicitly convertible to. However, constructing a std::string with a null char * pointer is undefined behavior, and your implementation has chosen to throw a std::logic_error exception that … Read more
For space separated strings, then you can do this: Output: string that have both comma and space Output:
There’s a fairly simple trick to do so, since the spec now guarantees vectors store their elements contiguously:
“helper function” is not a term that you would find in a standard, neither it has an exact definition… standard mentions “helper class” or “helper template” few times to refer to a class, which is not meant to be instantiated by end-users but it provides an useful functionality internally used within another class. Helper functions are (what I believe the … Read more
Actually as it is complicated to mix C# and C++ on unix, I am trying to convert C# to C++ Have you considered Mono? It is something that’s definitely worth checking before starting to learn C++ in order convert and run an existing .NET application on Unix. It’s also binary compatible meaning that you don’t even … Read more
typename and class are interchangeable in the basic case of specifying a template: and are equivalent. Having said that, there are specific cases where there is a difference between typename and class. The first one is in the case of dependent types. typename is used to declare when you are referencing a nested type that depends on another template parameter, such as the typedef in … Read more
You need to add the following:
Change to code to something like this: If you include this header file more than once in some source file, include guards will force compiler to generate class only once so it will not give class redefinition error.
With <iomanip>, you can use std::fixed and std::setprecision Here is an example And you will get output