conditional-tags - Read For Learn

A simple method for disabling WPML language switcher when meeting specific circumstances [closed]

Trouble with parent and child conditional tag to show content

If it is about child post types* or taxonomies**: // page/post/cpt parent check: $post_object = get_queried_object(); // check if the page has a parent if ( $post_object->post_parent ) // do stuff // cat/tax parent check: $taxonomy_object = get_the_category( get_query_var(‘cat’) ); // check if the cat/tag/tax has a parent: if ( $taxonomy_object->parent ) // do stuff … Read more

is_page conditional question

If the page slug is ‘contact’ then is_page(‘contact’) should work. You can check out the optional parameters for page in the codex here . Using post ID, e.g. 94 in your example will work regardless of permalink settings. If you want it to display for a specific template you can use is_page_template(‘contact.php’).

Identify a Woocommerce page by WordPress conditional tags

You can rewrite you code as <title> <?php if (!function_exists( ‘is_product_category’ )) { if( is_product_category( ‘cds’ ) ) { ?> CD <?php } elseif ( is_product_category( ‘dvds’ ) ) {?> DVD <?php } }else { wp_title( ‘|’, true, ‘right’ ); } ?>

If Parent or Current Page Is, Then Statement?

Use get_post_ancestors(): // get page ancestors $parents = get_post_ancestors( $post->ID ); // id of parent page you want to find $parent_id = 123; // check of $parent_id if ( $post->ID == $parent_id || in_array( $parent_id, $parents ) ) { echo ‘<a href=”#”>Link</a>’; }

If (category / tag checked) then (display header2php)

You can use the has_category() function for this: if ( has_category( ‘Grizzly Bears’ ) ) { get_header( ‘header2’ ); } else if ( has_category( ‘Peace Pipes’ ) ) { get_header( ‘header3’ ); } You can add the has_tag function as well. Both accept an array of term IDs, names or slugs if you want to … Read more

Use slug rather than id for $post->post_parent?

You can also get slug from direct post parent id like: $parent_id = $post->post_parent; $post_parent_slug = get_post_field( ‘post_name’, $parent_id ); Now you can replace: ‘2’ == $post->post_parent to ‘notes’ == $post_parent_slug Try this.

Display Footer Shortcode Different for Logged In Users

You can use a conditional tag to check if the user is logged in. Conditionals are very common in W, I would suggest you give this page a read. Here is an example. function footer_shortcode(){ if (is_user_logged_in()){ echo ‘ // Logged In Content ‘; }else{ echo ‘ // Logged Out Content ‘; } } add_shortcode(‘footerShortcode’, … Read more

Conditional tags inside a class

Your real problem is the god class. You put rendering, sanitation, validation, saving and fetching data, and registration into one class. Separate your tasks to make it it OOP, and let the main class be a very simple front controller that handles the initial registration only. Here is a rough start, illustrating how I would … Read more

Checking whether template part is loaded in a page

You can define a global variable in your theme functions.php global $mywidgets; $mywidgets = false; in your template part add global $mywidgets; $mywidgets = true; and in your functions you can check if its set to true: function my_function(){ global $mywidgets; $mywidgets = true; if ($mywidgets){ // YES Your template part is loaded }else{ // … Read more

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