You are trying to index into a scalar (non-iterable) value: When you call [y for y in test] you are iterating over the values already, so you get a single value in y. Your code is the same as trying to do the following: I’m not sure what you’re trying to get into your results … Read more
It seems there are already quite some questions here about relative import in python 3, but after going through many of them I still didn’t find the answer for my issue. so here is the question. I have a package shown below and I have a single line in test.py: now, I am in the … Read more
simply run Update after OP’s edit: There was a bug in the OP’s version of virtualenv, as described here. The problem was fixed by running:
There are specific libraries (like this one here) but maybe something very simple would do: Note: progressbar2 is a fork of progressbar which hasn’t been maintained in years.
Since two weeks, I’m trying and reading to solve this problem, but everything I tried didn’t worked 🙁 I’m using python 2.7. I do have, as far as I understand, a base64-string from the format: AAMkADk0ZjU4ODc1LTY1MzAtNDdhZS04NGU5LTAwYjE2Mzg5NDA1ZABGAAAAAAAZS9Y2rt6uTJgnyUZSiNf0BwC6iam6EuExS4FgbbOF87exAAAAdGVuAAC6iam6EuExS4FgbbOF87exAAAxj5dhAAA= I want to convert it to a hex-string. Which should result in 00000000194BD636AEDEAE4C9827C9465288D7F40700BA89A9BA12E1314B81606DB385F3B7B100000074656E0000BA89A9BA12E1314B81606DB385F3B7B10000318F97610000 I tried it with the following … Read more
**: exponentiation ^: exclusive-or (bitwise) %: modulus //: divide with integral result (discard remainder)
Your variable energies probably has the wrong shape: And that’s what happens if you read columnar data using your approach: Probably you can simply use instead. (P.S. Your code looks like it’s undecided about whether it’s data or elementdata. I’ve assumed it’s simply a typo.)
I have a script in which I am extracting value for every user and adding that in a list but I am getting “‘NoneType’ object has no attribute ‘append’”. My code is like I want to add last name in list. If its none then dont add it in list . Please help Note:p is … Read more
Sure. A for loop.
If you only have one reference to a string and you concatenate another string to the end, CPython now special cases this and tries to extend the string in place. The end result is that the operation is amortized O(n). e.g. used to be O(n^2), but now it is O(n). From the source (bytesobject.c): It’s … Read more