Great native python based answers given by other users. But here’s the nltk approach (just in case, the OP gets penalized for reinventing what’s already existing in the nltk library). There is an ngram module that people seldom use in nltk. It’s not because it’s hard to read ngrams, but training a model base on ngrams where n > 3 will result … Read more
string.format in Lua follows the same patterns as Printf in c: http://www.cplusplus.com/reference/clibrary/cstdio/printf/ There are some exceptions, for those see here: http://pgl.yoyo.org/luai/i/string.format
Break-down: 8 says that you want to show 8 digits 0 that you want to prefix with 0‘s instead of just blank spaces x that you want to print in lower-case hexadecimal. Quick example (thanks to Grijesh Chauhan): Output: Also see http://www.cplusplus.com/reference/cstdio/printf/ for reference.
Python has a % operator for this. See this reference for all supported format specifiers. You could as well use format:
Getting the name of the file without the extension: Prints: Documentation for os.path.splitext. Important Note: If the filename has multiple dots, only the extension after the last one is removed. For example: Prints: See other answers below if you need to handle that case.
A simple answer is: Xargs will do the trimming for you. It’s one command/program, no parameters, returns the trimmed string, easy as that! Note: this doesn’t remove all internal spaces so “foo bar” stays the same; it does NOT become “foobar”. However, multiple spaces will be condensed to single spaces, so “foo bar” will become “foo bar”. In addition it doesn’t remove … Read more
test‘s string equality operator doesn’t do globs.
I think this will work for you:
From the cppreference.com documentation Return value Negative value if lhs appears before rhs in lexicographical order. Zero if lhs and rhs compare equal. Positive value if lhs appears after rhs in lexicographical order. As you can see it just says negative, zero or positive. You can’t count on anything else. The site you linked isn’t incorrect. … Read more
Very simple. Just cast your char as an int. In your case, you need to get the specific Character from the String first and then cast it. Though cast is not required explicitly, but its improves readability.