Expression must be a modifiable lvalue

The assignment operator has lower precedence than &&, so your condition is equivalent to:

if ((match == 0 && k) = m)

But the left-hand side of this is an rvalue, namely the boolean resulting from the evaluation of the sub­expression match == 0 && k, so you cannot assign to it.

By contrast, comparison has higher precedence, so match == 0 && k == m is equivalent to:

if ((match == 0) && (k == m))

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