How to pass jQuery ajax URL value

Ajax url should be set to wp-admin/admin-ajax.php as ajax requests should be handled via wp-admin/admin-ajax in wordpress.
if ajaxurl is not defined you can get it by defining html attribute data-url as data-url="<?php echo get_admin_url().'admin-ajax.php'?>".

jQuery(document).ready(function($){
   $("#wp-submit").on('click',function(e){
      e.preventDefault();
      username = $("#userName").val();
      password = $("#passWord").val();
      ajaxurl  = $(this).data('url');
      $.ajax({

      type: "POST",
      url: ajaxurl,
      data : {

            name     : username,
            password : password,
            action   : 'check_user_login'

        },
       success: function(response){    
         if(response =='true')    {
             $("div#result").css('display', 'inline', 'important');
             $("div#result").html("Login Successful");
             console.log('true');
         }else{
            $("div#result").css('display', 'inline', 'important');
            $("div#result").html("Wrong username or password");
         }

       } 
    });
  });
});

Now Create your ajax function as

function user_login(){


   //do your stuff here
    global $wpdb;
    $username=$_POST['name']; 
    $password=$_POST['password']; 
    $hash = md5($password);
    $query = $wpdb->prepare( "SELECT * FROM `wp_users` WHERE `user_email` = %s AND `user_pass` = %s", $username, $hash );
    $result = $wpdb->get_results($query);
     if (count($result)==1) { echo 'true';
     echo '<span>Login Successful</span>'; exit(); 
    } else if(count($result) < 1) {
     echo 'false'; exit(); }
}

Now the ajax function should be hooked to hook
wp_ajax_* and wp_ajax_nopriv_*. Here, * is your action value i.e data.action so it becomes

 add_action('wp_ajax_nopriv_check_user_login','user_login');
 add_action('wp_ajax_check_user_login','user_login');