How to print a char array in C through printf?

The code posted is incorrect: a_static and b_static should be defined as arrays.

There are two ways to correct the code:

• you can add null terminators to make these arrays proper C strings:

#include <stdio.h>

int main(void) {
    char a_static[] = { 'q', 'w', 'e', 'r', '\0' };
    char b_static[] = { 'a', 's', 'd', 'f', '\0' };

    printf("value of a_static: %s\n", a_static);
    printf("value of b_static: %s\n", b_static);
    return 0;
}

Alternately, printf can print the contents of an array that is not null terminated using the precision field:

#include <stdio.h>

int main(void) {
    char a_static[] = { 'q', 'w', 'e', 'r' };
    char b_static[] = { 'a', 's', 'd', 'f' };

    printf("value of a_static: %.4s\n", a_static);
    printf("value of b_static: %.*s\n", (int)sizeof(b_static), b_static);
    return 0;
}

The precision given after the . specifies the maximum number of characters to output from the string. It can be given as a decimal number or as * and provided as an int argument before the char pointer.