I would recommend you use the literal notation, and the \s
character class:
//.. return str.replace(/\s/g, ''); //..
There’s a difference between using the character class \s
and just ' '
, this will match a lot more white-space characters, for example '\t\r\n'
etc.., looking for ' '
will replace only the ASCII 32 blank space.
The RegExp
constructor is useful when you want to build a dynamic pattern, in this case you don’t need it.
Moreover, as you said, "[\s]+"
didn’t work with the RegExp
constructor, that’s because you are passing a string, and you should “double escape” the back-slashes, otherwise they will be interpreted as character escapes inside the string (e.g.: "\s" === "s"
(unknown escape)).
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