You can simply use DataFrame.fillna
to fill the nan
‘s directly:
In [27]: df Out[27]: A B C 0 -0.166919 0.979728 -0.632955 1 -0.297953 -0.912674 -1.365463 2 -0.120211 -0.540679 -0.680481 3 NaN -2.027325 1.533582 4 NaN NaN 0.461821 5 -0.788073 NaN NaN 6 -0.916080 -0.612343 NaN 7 -0.887858 1.033826 NaN 8 1.948430 1.025011 -2.982224 9 0.019698 -0.795876 -0.046431 In [28]: df.mean() Out[28]: A -0.151121 B -0.231291 C -0.530307 dtype: float64 In [29]: df.fillna(df.mean()) Out[29]: A B C 0 -0.166919 0.979728 -0.632955 1 -0.297953 -0.912674 -1.365463 2 -0.120211 -0.540679 -0.680481 3 -0.151121 -2.027325 1.533582 4 -0.151121 -0.231291 0.461821 5 -0.788073 -0.231291 -0.530307 6 -0.916080 -0.612343 -0.530307 7 -0.887858 1.033826 -0.530307 8 1.948430 1.025011 -2.982224 9 0.019698 -0.795876 -0.046431
The docstring of fillna
says that value
should be a scalar or a dict, however, it seems to work with a Series
as well. If you want to pass a dict, you could use df.mean().to_dict()
.