Showing HTML if Post is In Certain Taxonomy Term

Try using has_term(). Something like this:

<?php if( has_term('term1', 'taxonomy_name', $post) ) { ?>
    <img src="http://www.site.com/wp-content/themes/site/img/stars-01.png" width="100" height="21" alt="default">
<?php }elseif ( has_term( 'term2', 'taxonomy_name', $post) ) { ?>
    <img src="http://www.site.com/wp-content/themes/site/img/stars-01.png" width="100" height="21" alt="default">
<?php  } else { ?>
    <img src="http://www.site.com/wp-content/themes/site/img/stars-01.png" width="100" height="21" alt="default">
<?php } ?>

You may also want to try using shorthand if/else statements, it tends to make the code a little cleaner and easier to read in situations like like this.

Same example using shorthand:

<?php if( has_term('term1', 'taxonomy_name', $post) ): ?>
    <img src="http://www.site.com/wp-content/themes/site/img/stars-01.png" width="100" height="21" alt="default">
<?php elseif ( has_term( 'term2', 'taxonomy_name', $post) ) :?>
    <img src="http://www.site.com/wp-content/themes/site/img/stars-01.png" width="100" height="21" alt="default">
<?php else: ?>
    <img src="http://www.site.com/wp-content/themes/site/img/stars-01.png" width="100" height="21" alt="default">
<?php endif; ?>

Hope this helps!