C char* to int conversion
atoi can do that for you Example:
atoi can do that for you Example:
The %c conversion specifier won’t automatically skip any leading whitespace, so if there’s a stray newline in the input stream (from a previous entry, for example) the scanf call will consume it immediately. One way around the problem is to put a blank space before the conversion specifier in the format string: The blank in the format string tells scanf to … Read more
I guess you want to make arrays of pointers instead of arrays of characters. Try this:
The code posted is incorrect: a_static and b_static should be defined as arrays. There are two ways to correct the code: you can add null terminators to make these arrays proper C strings: Alternately, printf can print the contents of an array that is not null terminated using the precision field: The precision given after the . specifies the maximum number of characters … Read more
Notice you’re not dynamically allocating the variable, which pretty much means the data inside str, in your function, will be lost by the end of the function. You should have: Then, when you call the function, the type of the variable that will receive the data must match that of the function return. So, you should … Read more
Interesting answers but the docs say differently: Use the GetNumericValue methods to convert a Char object that represents a number to a numeric value type. Use Parse and TryParse to convert a character in a string into a Char object. Use ToString to convert a Char object to a String object. http://msdn.microsoft.com/en-us/library/system.char.aspx
Or, if the string already exists: Edit: I’m still not completely sure I understand the question. But if it’s something like what JoshG is suggesting, that you want up to length characters, or until a null terminator, whichever comes first, then you can use this:
It’s the remainder operator and is used to get the remainder after integer division. Lots of languages have it. For example: Apparently it is not the same as the modulo operator entirely.
The language specification is where null is defined, and it says There is also a special null type, the type of the expression null, which has no name. Because the null type has no name, it is impossible to declare a variable of the null type or to cast to the null type. The null … Read more
A: The std::string class has a constructor that takes a char const*, so you simply create an instance to do your conversion. B: Instances of std::string have a c_str() member function that returns a char const* that you can use to convert back to char const*.