Checking for __iter__ works on sequence types, but it would fail on e.g. strings in Python 2. I would like to know the right answer too, until then, here is one possibility (which would work on strings, too): from __future__ import print_function try: some_object_iterator = iter(some_object) except TypeError as te: print(some_object, ‘is not iterable’) The … Read more
An Iterable is a simple representation of a series of elements that can be iterated over. It does not have any iteration state such as a “current element”. Instead, it has one method that produces an Iterator. An Iterator is the object with iteration state. It lets you check if it has more elements using hasNext() and move to the next element … Read more
As far as I can tell, making a class object iterable by using a metaclass works just fine: Results in: Here’s an example where I actually track the cars generated: Note that if you’re using python3.x, to use a metaclass you do: Rather than: which likely explains the problem that you’re experiencing
It’s pretty simple really: There is also the step value, which can be used with any of the above: The key point to remember is that the :stop value represents the first value that is not in the selected slice. So, the difference between stop and start is the number of elements selected (if step is 1, the default). The other feature is that start or stop may be a negative number, which … Read more
Direct Answer In the code here: change sourceCode.split to sourceCode.split(). If you want to know more about this error, read below: When debugging, you’d better remove the try…except block, especially an “expect Exception” block, which is so generic that you will get lost about what is going wrong. When removed the try…except block and run these code again, … Read more
Your problem is with this line: It tries to take cow[n], which returns an integer, and make it a list. This doesn’t work, as demonstrated below: Perhaps you meant to put cow[n] inside a list: See a demonstration below: Also, I wanted to address two things: Your while-statement is missing a : at the end. It is considered very dangerous to … Read more
It’s pretty simple really: There is also the step value, which can be used with any of the above: The key point to remember is that the :stop value represents the first value that is not in the selected slice. So, the difference between stop and start is the number of elements selected (if step is 1, the default). The other feature is that start or stop may be a negative number, which … Read more
It’s pretty simple really: There is also the step value, which can be used with any of the above: The key point to remember is that the :stop value represents the first value that is not in the selected slice. So, the difference between stop and start is the number of elements selected (if step is 1, the default). The other feature is that start or stop may be a negative number, which … Read more
Your problem is with this line: It tries to take cow[n], which returns an integer, and make it a list. This doesn’t work, as demonstrated below: Perhaps you meant to put cow[n] inside a list: See a demonstration below: Also, I wanted to address two things: Your while-statement is missing a : at the end. It is considered very dangerous to … Read more