Firstly you need to learn the differences between references and pointers and then the difference between pass-by-reference and pass-by-pointer. A function prototype of the form: expects a function call of the type: Whereas, a prototype of the form: expects a function call of the type: Using the same logic, if you wish to pass the vector by reference, … Read more
The & symbol in a C++ variable declaration means it’s a reference. It happens to be a reference to a pointer, which explains the semantics you’re seeing; the called function can change the pointer in the calling context, since it has a reference to it. So, to reiterate, the “operative symbol” here is not *&, that combination … Read more
Check if you are referencing an assembly which in turn referencing an old version of unity. For example let’s say you have an assembly called ServiceLocator.dll which needs an old version of Unity assembly, now when you reference the ServiceLocator you should provide it with the old version of Unity, and that makes the problem. May be the output … Read more
Can someone please explain this to me? This doesn’t make any sense to me. I copy a dictionary into another and edit the second and both are changed. Why is this happening?
Check if you are referencing an assembly which in turn referencing an old version of unity. For example let’s say you have an assembly called ServiceLocator.dll which needs an old version of Unity assembly, now when you reference the ServiceLocator you should provide it with the old version of Unity, and that makes the problem. … Read more
If you will place your definitions in this order then the code will be compiled The definition of function doSomething requires the complete definition of class Ball because it access its data member. In your code example module Player.cpp has no access to the definition of class Ball so the compiler issues an error.
and Are just the same thing. so does: And once you declared the reference, you can think of it just like the actual variable itself. so you don’t need particular operator to dereference it. when passing variables through function arguments, the raw object is always shallow copied in memory to the new variable in the … Read more
With new_list = my_list, you don’t actually have two lists. The assignment just copies the reference to the list, not the actual list, so both new_list and my_list refer to the same list after the assignment. To actually copy the list, you have various possibilities: You can use the builtin list.copy() method (available since Python 3.3):new_list = old_list.copy() You can slice it:new_list … Read more
static means that the variable or method marked as such is available at the class level. In other words, you don’t need to create an instance of the class to access it. So, instead of creating an instance of Foo and then calling doStuff like this: You just call the method directly against the class, … Read more
Arguments are passed by assignment. The rationale behind this is twofold: the parameter passed in is actually a reference to an object (but the reference is passed by value) some data types are mutable, but others aren’t So: If you pass a mutable object into a method, the method gets a reference to that same object and you can mutate … Read more