In binary, 0xE9 looks like 1110 1001
. If you read about UTF-8 on Wikipedia, you’ll see that such a byte must be followed by two of the form 10xx xxxx
. So, for example:
>>> b'\xe9\x80\x80'.decode('utf-8') u'\u9000'
But that’s just the mechanical cause of the exception. In this case, you have a string that is almost certainly encoded in latin 1. You can see how UTF-8 and latin 1 look different:
>>> u'\xe9'.encode('utf-8') b'\xc3\xa9' >>> u'\xe9'.encode('latin-1') b'\xe9'
(Note, I’m using a mix of Python 2 and 3 representation here. The input is valid in any version of Python, but your Python interpreter is unlikely to actually show both unicode and byte strings in this way.)
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