How to find list intersection?
If order is not important and you don’t need to worry about duplicates then you can use set intersection:
If order is not important and you don’t need to worry about duplicates then you can use set intersection:
The error is here: You are passing the first item of words, instead of the array. Instead, pass the array to the function: Problem solved! Here’s a breakdown of what the problem was: I’m guessing in your browser (chrome throws a different error), words[] == words[0], so when you call hasLetter(“a”,words[]);, you are actually calling hasLetter(“a”,words[0]);. So, in essence, … Read more
If I start with a 3×4 array, and concatenate a 3×1 array, with axis 1, I get a 3×5 array: Note that both inputs to concatenate have 2 dimensions. Omit the :, and x[:,-1] is (3,) shape – it is 1d, and hence the error: The code for np.append is (in this case where axis is specified) So with a … Read more
Depending on the encoding you wish to use:
The error is actually “lvalue required as left operand of assignment”. It means that your a[i][j] is giving you a temporary object. This happens when you return from a function by value. A function call that returns by value is an rvalue expression, and you cannot use an rvalue expression as the left operand of an assignment. You need to … Read more
Quick and dirty using jQuery:
list.toString() is good enough. The interface List does not define a contract for toString(), but the AbstractCollection base class provides a useful implementation that ArrayList inherits.
You can use it like this: Also works for multi-line array declaration
Ways to clear an existing array A: Method 1 (this was my original answer to the question) This code will set the variable A to a new empty array. This is perfect if you don’t have references to the original array A anywhere else because this actually creates a brand new (empty) array. You should be careful with this method because … Read more