Even though this question may get down voted – because not enough information has been provided and it’s fairly easy to find tutorials elsewhere, I’ll help you out. In your functions.php file in your theme, you need to do this: add_action( ‘wp_enqueue_scripts’, ‘wp5849_scripts’ ); function wp5849_scripts() { if ( is_front_page() ) : wp_enqueue_style(‘TBDhome’, get_stylesheet_directory_uri() . … Read more
Try using get_post_type() instead: if ( is_single() && ‘post_type’ == get_post_type() ) { // Do something } The is_post_type() conditional is deprecated. But even when it existed, it returned true if the current post is any registered custom post type. It has been replaced with post_type_exists(). (More information on Post Type conditional tags.)
You cad add it via functions.php with a hook, instead of inside the loop (you don’t really want to add a loop to header.php): function add_author_meta() { if (is_single()){ global $post; $author = get_the_author_meta(‘user_nicename’, $post->post_author); echo “<meta name=\”author\” content=\”$author\”>”; } } add_action( ‘wp_enqueue_scripts’, ‘add_author_meta’ );
DOING_AJAX and WP_ADMIN (this constant is checked within is_admin() ) are defined in admin-ajax.php and set tro true. Both are not very helpfull in this situation. Add a parameter to your ajax request if the request come from the front-end: <?php function my_action_javascript() { ?> <script type=”text/javascript” > jQuery(document).ready(function($) { var data = { action: … Read more
An AJAX request is a new request to the server, and it is a request to admin-ajax.php. That is not a single post page. Any logic that depends on is_single() or any other page level template tags like it, won’t work. If your AJAX callback needs that sort of information you must pass it to … Read more
I ended up using this code: <?php global $post; $children = get_pages( array( ‘child_of’ => $post->ID ) ); if ( is_page() && $post->post_parent ) : ?> This is a child-page. <?php elseif ( is_page() && count( $children ) > 0 ) : ?> This is a parent-page (with one or more children) <?php else : … Read more
Make sure your code runs in wp_enqueue_scripts action hook. Also checkout your script handle ‘owl.carousel.js’. In wp_script_is(), it is not the same than in the 2 later functions in which you enter it as ‘owl.carousel.min.js’. add_action( ‘wp_enqueue_scripts’, ‘enqueue_properties_scripts’ ); function enqueue_properties_scripts() { if ( ‘properties’ === get_post_type() ) { if ( wp_script_is( ‘owl.carousel.min.js’, ‘enqueued’ ) … Read more
As in this question: How to execute conditional script when on new customize.php (Theme Customize) screen global $wp_customize; if ( isset( $wp_customize ) ) { // do stuff }
You have a basic mistake in your code. The following code if ( !is_page(‘my-page’) ) { means that if you are not on that page, deregister the scripts. Have a look at the php operators ! -> Not !$x True if $x is not true Also, why not exclude this specific page when you initially … Read more
Your conditional logic makes sense as well but you’re probably looking for this: if ( ‘page’ == get_option(‘show_on_front’) ) { // do something } Hint: You can append options.php to the WordpPress admin url like this: http://www.example.com/wp-admin/options.php to see all options. ( that’s where I found the answer for you .)