It’s an old question but I’d add something potentially useful: I know you wrote your example in raw Python lists, but if you decide to use numpy arrays instead (which would be perfectly legit in your example, because you seem to be dealing with arrays of numbers), there is (almost exactly) this command you said you made … Read more
They are the same number. What differs is their representation; the Python native type uses a “sane” representation, and the NumPy type uses an accurate representation.
As simple as that. Basically you don’t need it if the variable is int.
float and double are floating binary point types. In other words, they represent a number like this: The binary number and the location of the binary point are both encoded within the value. decimal is a floating decimal point type. In other words, they represent a number like this: Again, the number and the location of the decimal point are both encoded within the value – that’s … Read more
float and double are floating binary point types. In other words, they represent a number like this: The binary number and the location of the binary point are both encoded within the value. decimal is a floating decimal point type. In other words, they represent a number like this: Again, the number and the location of the decimal point are both encoded within the value – that’s … Read more
You just need to cast at least one of the operands to a float: or or (unnecessary)
First, the function, for those who just want some copy-and-paste code: This is valid in Python 2.7 and 3.1+. For older versions, it’s not possible to get the same “intelligent rounding” effect (at least, not without a lot of complicated code), but rounding to 12 decimal places before truncation will work much of the time: … Read more
Well I would atleast clean it up as follows:
Keep multiplying the number after decimal by 2 till it becomes 1.0: and the result is in reverse order being .01
Integer division occurs, then the result, which is an integer, is assigned as a float. If the result is less than 1 then it ends up as 0. You’ll want to cast the expressions to floats first before dividing, e.g.