Python 3.6.0 syntax error “Missing parentheses in call to ‘print’ [duplicate]
This is very basic problem but because you seem completely new to everything… The print “statement” in Python 3.x is a function that uses parenthesis so: Is now
This is very basic problem but because you seem completely new to everything… The print “statement” in Python 3.x is a function that uses parenthesis so: Is now
This always works for me: However, this doesn’t make PHP to show parse errors – the only way to show those errors is to modify your php.ini with this line: (if you don’t have access to php.ini, then putting this line in .htaccess might work too):
Replace exit with break. Exit isn’t a way to exit loops in Python. break statement docs
I had the same problem. This worked for me on mac:
I’m in Python 3.3 and I’m only entering these 3 lines: I’m getting this error: What could I be doing wrong? Edit: If anyone comes across this question, the solution I found was to download Idlex and use its IDLE version, which allows multiple lines. Screenshot: http://imgur.com/AJSrhhD
Looks like your problem is that you are trying to run python test.py from within the Python interpreter, which is why you’re seeing that traceback. Make sure you’re out of the interpreter, then run the python test.py command from bash or command prompt or whatever.
Looks like your problem is that you are trying to run python test.py from within the Python interpreter, which is why you’re seeing that traceback. Make sure you’re out of the interpreter, then run the python test.py command from bash or command prompt or whatever.
Try this in the console: Here is what you will get: In other words, your app is attempting to parse undefined, which is not valid JSON. There are two common causes for this. The first is that you may be referencing a non-existent property (or even a non-existent variable if not in strict mode). The second … Read more
This particular error is one annoying fact about v8. In most cases your JavaScript is broken in some way. For example missing a } or something like that. Example given, this will yield “Unexpected end of input” too: But the root cause of the problems seems to be that the requested JSON url has a Content-Type of text/html which Chrome apparently tries … Read more
In my case, I was trying to parse an empty JSON: In other words, what happened was the following: