It’s a reference to the current object, it’s most commonly used in object oriented code. Reference: http://www.php.net/manual/en/language.oop5.basic.php Primer: http://www.phpro.org/tutorials/Object-Oriented-Programming-with-PHP.html Example: This stores the ‘Jack’ string as a property of the object created.
this means pointer to the object, so *this is an object. So you are returning an object ie, *this returns a reference to the object.
View.getContext(): Returns the context the view is currently running in. Usually the currently active Activity. Activity.getApplicationContext(): Returns the context for the entire application (the process all the Activities are running inside of). Use this instead of the current Activity context if you need a context tied to the lifecycle of the entire application, not just … Read more
Javascripts .call() and .apply() methods allow you to set the context for a function. Now you can call: Which would alert FOO. The other way around, passing obj_b would alert BAR!!. The difference between .call() and .apply() is that .call() takes a comma separated list if you’re passing arguments to your function and .apply() needs … Read more
You code does not follow the right principles. Wrap everything in the document.ready function. Avoid global variables wherever possible. Make use of the fact that jQuery manages this for you. this will always be what you expect if you pass callback functions directly instead of calling them yourself.
In jQuery functions, this most often refers to the actual DOM element you’re dealing with, whereas $(this) returns a jQuery object that wraps the element. In JavaScript, this always refers to the current scope. Many of jQuery’s functions will set that scope to be the element you’re working with. For instance The point is, that the jQuery object has all the … Read more
See, “this” keyword refers to current object due to which method is under exceution. As, you cannot call static method using instance of class. That is why, “this” can’t be used in the above example in a static method as it is trying to print current instance wich is not at all created. So, I … Read more
You have to use That is because even if it is true that your grid is a pointer, you have allocated in the are pointed by its memory an array of Square object. So when you use the [] operator you are obtaining an object of type Square and not a Square* and for a Square object you hve to use the . operator and … Read more
You have to use That is because even if it is true that your grid is a pointer, you have allocated in the are pointed by its memory an array of Square object. So when you use the [] operator you are obtaining an object of type Square and not a Square* and for a Square object you hve to use the . operator and … Read more
You rewrite the context of the class method when you pass it to props like this because of JS OOP system. So to make it work there are several approaches: 1) This is not so good because bind always returns new function and your component will re-render even if there are no updates in props … Read more