Pop index out of range

To get the final value of a list pop’ed, you can do it this way:

>>> l=range(8)
>>> l
[0, 1, 2, 3, 4, 5, 6, 7]
>>> l.pop(4)                    # item at index 4
4
>>> l
[0, 1, 2, 3, 5, 6, 7]
>>> l.pop(-1)                   # item at end - equivalent to pop()
7
>>> l
[0, 1, 2, 3, 5, 6]
>>> l.pop(-2)                   # one left of the end 
5
>>> l
[0, 1, 2, 3, 6]
>>> l.pop()                     # always the end item
6
>>> l
[0, 1, 2, 3]

Keep in mind that pop removes the item, and the list changes length after the pop. Use negative numbers to index from the end of a list that may be changing in size, or just use pop() with no arguments for the end item.

Since a pop can produce these errors, you often see them in an exception block:

>>> l=[]
>>> try:
...    i=l.pop(5)
... except IndexError:
...    print "sorry -- can't pop that"
... 
sorry -- can't pop that

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