Is there a way to end the program if statement is false?
This should end it!
This should end it!
The problem is the semicolon after the if. The grammar is if ( condition ) expression-or-block { else expression-or-block } Since ; is an empty expression, this works for an if clause and nothing happens in the then clause – in your case syntactically there is no else clause, since your if statement statements ends … Read more
else doesn’ take any condition, but you’ve written this: which doesn’t do what you intend it to do. You want to do thos: Notice the difference. Also, there can be at most one else block, associated with an if block Or a chain of if, else-if, else-if blocks. That is, you can write this: Or, … Read more
You have to reimplement it using <xsl:choose> tag:
You are comparing, not assigning: You compare values with == or ===. You assign values with =. You could write less code to achieve the same result too, with a switch statement, or just a bunch of ifs without the elseifs. I would make a function for it, like this:
With “or”. As the Lua manual clearly states.
If your $VARIABLE is a string containing spaces or other special characters, and single square brackets are used (which is a shortcut for the test command), then the string may be split out into multiple words. Each of these is treated as a separate argument. So that one variable is split out into many arguments: The same will be true for any … Read more
You can use numpy.where: Error is better explain here. Slowier solution with apply, where need axis=1 for data processing by rows: Also is possible use loc, but sometimes data can be overwritten:
Because your else isn’t attached to anything. The if without braces only encompasses the single statement that immediately follows it. Not using braces is generally viewed as a bad practice because it can lead to the exact problems you encountered. In addition, using a switch here would make more sense. Note that instead of an infinite for loop I used a while(boolean), making it … Read more
The problem is the semicolon after the if. The grammar is if ( condition ) expression-or-block { else expression-or-block } Since ; is an empty expression, this works for an if clause and nothing happens in the then clause – in your case syntactically there is no else clause, since your if statement statements ends … Read more