Is there a TRY CATCH command in Bash

Is there a TRY CATCH command in Bash? No. Bash doesn’t have as many luxuries as one can find in many programming languages. There is no try/catch in bash; however, one can achieve similar behavior using && or ||. Using ||: if command1 fails then command2 runs as follows Similarly, using &&, command2 will run if command1 is successful The closest approximation of try/catch is as follows Also bash contains some error … Read more

What is the $? (dollar question mark) variable in shell scripting?

$? is used to find the return value of the last executed command. Try the following in the shell: If somefile exists (regardless whether it is a file or directory), you will get the return value thrown by the ls command, which should be 0 (default “success” return value). If it doesn’t exist, you should get a number other then 0. The … Read more

Meaning of $? (dollar question mark) in shell scripts

This is the exit status of the last executed command. For example the command true always returns a status of 0 and false always returns a status of 1: From the manual: (acessible by calling man bash in your shell) $?       Expands to the exit status of the most recently executed foreground pipeline. By convention an exit status of 0 means success, and non-zero return status … Read more

How do I set a variable to the output of a command in Bash?

In addition to backticks `command`, command substitution can be done with $(command) or “$(command)”, which I find easier to read, and allows for nesting. Quoting (“) does matter to preserve multi-line variable values; it is optional on the right-hand side of an assignment, as word splitting is not performed, so OUTPUT=$(ls -1) would work fine.

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