Try this function wpse66115_redirect_to_sub_site() { if ( is_main_site() ) { if ( is_user_logged_in() ) { } else { exit( wp_redirect( ‘http://old.heiledeg.no’, 301 ) ); } } } add_action( ‘parse_request’, ‘wpse66115_redirect_to_sub_site’ );
You can’t do what you’re trying to do. If you want to output a shortcode you need to do it in the content or template. You can’t place one with CSS.
Posts Per Page with a button to add more Posts
I found the solution, I had to do the right ajax actions… For the second dropdown, I had to first detect the click on the statically created div then detect the change on the dynamically created dropdown. Here the correct code: <?php /** * Plugin Name: demoConnecteurs * Description: Plugin de démo des connecteurs Jenkins … Read more
To display only assigned category you need to change hide_empty to true. Please see the modified code: $args = array( ‘hierarchical’ => 1, ‘show_option_none’ => ”, ‘hide_empty’ => true, ‘parent’ => 134, ‘taxonomy’ => ‘product_cat’ ); $subcats = get_categories($args); echo ‘<ul class=”wooc_sclist”>’; foreach ($subcats as $sc) { $link = get_term_link( $sc->slug, $sc->taxonomy ); echo ‘<li><a … Read more
Your code does not need to use output buffering anywhere. There’s nowhere that you need it. Your shortcode function is already properly using return for the output output, so nothing needs to be captured, and your popup_bootmodal_form() function is outputting in wp_footer, which is fine, and doesn’t need to be captured either.
There’s no permalink property of a product. Permalinks are not stored in the database, because they’re generated based on a number of external factors. Therefore you need to use a function to retrieve the permalink. In WooCommerce the best way to do this is with: function fpd_custom_order_item_values($_product) { $url = $_product->get_permalink(); echo ‘<p>’ . esc_url( … Read more
You have the PHP IF statement needed, is_user_logged_in(). Just add your button to that and you should be good. Something this… <?php if (is_user_logged_in()) { echo ‘<button type=”button” class=”show-btn”>LOG IN</button>’; } else { echo ‘<button type=”button” class=”show-btn”>REGISTER</button>’; }; ?> Note: You have an extra </div> in your code above.
There is no such thing as an AJAX call that’s inside the loop. The server has no idea what page or where on that page an ajax call is coming from unless you explicitly send it that data as a part of the ajax call. You’re going to need to send some data to the … Read more
Show the subcategory name based on current product