TL;DR: dependency conflicts: Updating one requires (by it’s requirements) to downgrade another You are right: is actually the way to go1. Conda always tries to upgrade the packages to the newest version in the series (say Python 2.x or 3.x). Dependency conflicts But it is possible that there are dependency conflicts (which prevent a further … Read more
Can you please let me know what is incorrect in below DFS code. It’s giving correct result AFAIK, but I don’t know when it will fail. Output:
I’ve been stuck on this question for quite sometime and just can’t figure it out. I just want to be able to understand what I’m missing and why it’s needed. What I need to do is make a function which adds each given key/value pair to the dictionary. The argument key_value_pairs will be a list … Read more
You may want to build a virtualenv of python3, then install packages of python3 after activating the virtualenv. So your system won’t be messed up 🙂 This could be something like:
exponent is a 1D array. This means that exponent[0] is a scalar, and exponent[0][i] is trying to access it as if it were an array. Did you mean to say: or even ?
This is functionally equivalent to this:
Possible Duplicate:Python Ternary OperatorPutting a simple if-then statement on one line Is there a way to compress an if/else statement to one line in Python?I oftentimes see all sorts of shortcuts and suspect it can apply here too.
You can use df.loc[i], where the row with index i will be what you specify it to be in the dataframe.
The easiest way I found is this: Just open another (non-running, existing) notebook on the same kernel, and the issue is magically gone; you can again save the notebooks that were previously showing the _xsrf error. If you have already closed the Jupyter home page, you can find a link to it on the terminal … Read more
The best way is probably to use the list method .index. For the objects in the list, you can do something like: with any special processing you need. You can also use a for/in statement with enumerate(arr) Example of finding the index of an item that has value > 100. Source