Transpose/Unzip Function (inverse of zip)?
zip is its own inverse! Provided you use the special * operator. The way this works is by calling zip with the arguments: … except the arguments are passed to zip directly (after being converted to a tu
list
TypeError: ‘float’ object is not subscriptable
PriceList[0] is a float. PriceList[0][1] is trying to access the first element of a float. Instead, do or
How to get the list of all installed color schemes in Vim?
Type :colorscheme then Space followed by TAB. or as Peter said, :colorscheme then Space followed by CTRLd The short version of the command is :colo so you can use it in the two previous commands, instead of using the “long form”. If you want to find and preview more themes, there are various websites like … Read more
Is there a short contains function for lists?
You can use this syntax: Also, inverse operator: It works fine for lists, tuples, sets and dicts (check keys). Note that this is an O(n) operation in lists and tuples, but an O(1) operation in sets and dicts.
TypeError: ‘float’ object is not subscriptable
PriceList[0] is a float. PriceList[0][1] is trying to access the first element of a float. Instead, do or
Converting array to list in Java
In your example, it is because you can’t have a List of a primitive type. In other words, List<int> is not possible. You can, however, have a List<Integer> using the Integer class that wraps the int primitive. Convert your array to a List with the Arrays.asList utility method. See this code run live at IdeOne.com.
Why does this iterative list-growing code give IndexError: list assignment index out of range?
j is an empty list, but you’re attempting to write to element [0] in the first iteration, which doesn’t exist yet. Try the following instead, to add a new element to the end of the list: Of course, you’d never do this in practice if all you wanted to do was to copy an existing list. You’d just … Read more
List changes unexpectedly after assignment. Why is this and how can I prevent it?
With new_list = my_list, you don’t actually have two lists. The assignment just copies the reference to the list, not the actual list, so both new_list and my_list refer to the same list after the assignment. To actually copy the list, you have various possibilities: You can use the builtin list.copy() method (available since Python 3.3):new_list = old_list.copy() You can slice it:new_list … Read more
What does the list() function do in Python?
list() converts the iterable passed to it to a list. If the itertable is already a list then a shallow copy is returned, i.e only the outermost container is new rest of the objects are still the same.
Accessing the index in ‘for’ loops?
Using an additional state variable, such as an index variable (which you would normally use in languages such as C or PHP), is considered non-pythonic. The better option is to use the built-in function enumerate(), available in both Python 2 and 3: